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Sight distance is calculated using the following formula. <br /> d = (velocity)(time) = 1.47V(J+ta) <br /> Where: <br /> d=minimum sight distance along the major highway from the intersection(ft) <br /> V=design speed on major highway(mph).Posted speed limit is 65mph <br /> J=perception-reaction time(sec). MnDOT uses 2.Osec <br /> tQ=time(sec)required to traverse distance S to clear the major highway pavement <br /> S=D+W+L <br /> D=distance from the near edge of the pavement to the front of the stopped vehicle(ft) M nDOT <br /> uses 10ft <br /> W=width of the pavement along the path of the crossing vehicle(ft).See Figure 6. <br /> L=Overall length of the vehicle(ft). MnDOT uses 30ft for passenger vehicle,30ft for single unit <br /> truck,and 69ft for a WB-62 semi-truck <br /> S =2(tQ)Z +vo�ta) +Do <br /> a=acceleration of the vehicle from stop.Assumed at 3.8(ft/sec2)° <br /> vo =initial velocity of the vehicle.Since vehicle is at rest,0(mph) <br /> Do=initial distance at stop bar is considered 0(ft) <br /> TH 371 at CSAH 29 Intersection Evaluation 10 <br />